Day 16: Exceptions - HackerRank 30 days of code solution

Objective
Today, we're getting started with Exceptions by learning how to parse an integer from a string and print a custom error message.

Task
Read a string, , and print its integer value; if  cannot be converted to an integer, print Bad String.

Note: You must use the String-to-Integer and exception handling constructs built into your submission language. If you attempt to use loops/conditional statements, you will get a  score.

Input Format

A single string, .

Constraints

• , where  is the length of string .
•  is composed of either lowercase letters () or decimal digits ().

Output Format

Print the parsed integer value of , or Bad String if  cannot be converted to an integer.

Sample Input 0

3

Sample Output 0

3

Sample Input 1

za

Sample Output 1

Bad String

Explanation

Sample Case  contains an integer, so it should not raise an exception when we attempt to convert it to an integer. Thus, we print the .
Sample Case  does not contain any integers, so an attempt to convert it to an integer will raise an exception. Thus, our exception handler prints Bad String.

Solution :

import java.io.*;

import java.util.*;

import java.text.*;

import java.math.*;

import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {

        Scanner in = new Scanner(System.in);

        String S = in.next();

      

        try{

            Integer i = Integer.parseInt(S);

            System.out.println(i);

          

        }catch(NumberFormatException nfe){

            System.out.println("Bad String");

        }

    }

}