Day 19: Interfaces - HackerRank 30 days of code solution

Objective
Today, we're learning about Interfaces. Check out the Tutorial tab for learning materials and an instructional video!

Task
The AdvancedArithmetic interface and the method declaration for the abstract divisorSum(n) method are provided for you in the editor below.

Complete the implementation of Calculator class, which implements the AdvancedArithmetic interface. The implementation for the divisorSum(n) method must return the sum of all divisors of .

Input Format

A single line containing an integer, .

Constraints

Output Format

You are not responsible for printing anything to stdout. The locked template code in the editor below will call your code and print the necessary output.

Sample Input

6

Sample Output

I implemented: AdvancedArithmetic
12

Explanation

The integer  is evenly divisible by , , , and . Our divisorSum method should return the sum of these numbers, which is . The Solution class then prints  on the first line, followed by the sum returned by divisorSum (which is ) on the second line.

Solution :

import java.io.*;

import java.util.*;

interface AdvancedArithmetic{

   int divisorSum(int n);

}

//Write your code here

class Calculator implements AdvancedArithmetic {

    private int n;

    public int divisorSum (int n){

        int sum = 0;

        for(int i = 1; i<= n ; i++){

            if(n % i == 0){

                sum +=i;

            }

        }

        return sum;

    }

}

class Solution {

    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);

        int n = scan.nextInt();

        scan.close();

        

      AdvancedArithmetic myCalculator = new Calculator(); 

        int sum = myCalculator.divisorSum(n);

        System.out.println("I implemented: " + myCalculator.getClass().getInterfaces()[0].getName() );

        System.out.println(sum);

    }

}